Bianca C. answered • 01/23/21
Algebra and English Tutor
*For solving systems of linear equations through substitution, you will need to write one of the expressions equal to a variable of your choice and then plug this value into the same variable in the other expression. Let me work through this with you...
Hello Ashlyn! I hope this helps:
Original Expressions:
x+4y=6
x-y=1
Let's set x-y=1 equal to x.
We will want to add y to both sides of the equation.
We will then end up with x = y+1.
^The expression is now set equal to x.
Since x = (y+1) now, we can plug this expression into the other expression (x+4y=6).
So,
x+4y=6 becomes...
(y+1)+4y =6
Let's Simplify! We will need to combine like terms.
y+1+4y = 6 becomes 5y+1=6
Great! Now we need to find the value of y.
So, subtract 1 from both sides.
We are now left with 5y = 5
If we divide y from both sides, we end up with 1.
So, y=1.
Great, the harder part is done!
Now you can plug this number into either of the equations and solve for x. I will use x+4y=6 for this example.
So now,
x+4y=6 becomes x+4(1) =6 because we know that y is equal to 1.
Simplify!
x+4=6
Subtract 4 from both sides
We now end with x=2.
The solutions to this system of linear equations is x=2 and y=1. If you were to plug this into either equation, the outcome would be correct. :)
Ashlyn U.
but I'm stuck on another problem that is not the same though01/23/21
Bianca C.
Feel free to message the problem to me.01/23/21
Bianca C.
I will see what I can do.01/23/21
Ashlyn U.
i just posted a new one that i don´t understand Bianca C.01/23/21
Bianca C.
hmm...it seems I cannot find the post.01/23/21
Ashlyn U.
its at the very top01/23/21
Ashlyn U.
of my profile page01/23/21
Ashlyn U.
its the post that says Solve the system of linear equations.01/23/21
Ashlyn U.
It helped a lot01/23/21