What is the equation of a line when the y intercept is (0,-2) and passes through the point (5,1) ?

Answer 1

HI Jordan

the equation of the line is y = mx + b. b is your y intercept. so when 0 is zero, y is -2

Let's say (0,-2) is (x,y)

and

(5,1) is (x1, y1)

The equation of the line is also written y - y1 = m (x - x1)

solve for m (m is your slope)

-2 - 1 = m (0 - 5)

-3 = -5m

3/5 = m

Now go back to y = mx + b and plug in "m" and "b" to get your equation

y = (3/5)m- 2

let me know if any questions.

Miss Julie