Write an equation in slope-intercept form of the line that passes through the points (-4,2) and (1,-1).

Answer 1

First, let's find the slope of the line. The equation for this is (y2 - y1) / (x2 - x1) = m

Substitute the given values:

(2 - (-1)) / (-4 - 1) = 3/-5 = - 3/5 = m

Calling any point of the line (x, y), the slope expression is (y - y1) / (x - x1) = m,

y - (-1) / (x - 1) = -3/5

y + 1 / (x - 1) = -3/5

with some algebraic manipulation

y = -3/5x -2/5 slope = -3/5 y intercept = -2/5

check my math.

Answer 2

slope = m = (2--1)/(-4-1) = 3/-5 = -3/5

y=mx + b

y=-(3/5)x + b

-1 = -3/5 + b

b = -2/5

y = (-3/5)x - 2/5

where -3/5 = slope and -2/5 = y intercept