Write an equation for a line that is perpendicular to y = -1/4x + 7 and passes through thenpoint (3,-5)

Answer 1

The slopes of perpendicular lines are reciprocals and have opposite signs. The slope of the given line is -1/4 so our new slope will be 4. Now we use point-slope form,(y-y₁) = m(x-x₁), where x₁ and y₁ are the x and y values of the given point and m is the new slope, 4. Then we solve for y to get the equation in slope-intercept form.

y - (-5) = 4(x-3)

y + 5 = 4x - 12

y = 4x - 17