Kathy P. answered 01/21/21
Mechanical Engineer with 10+ teaching and tutoring experience
Given: Tens digit of a two-digit number
is 4 times the ones digit.
The sum of the digits is 10.
Find: The original number.
SOLUTION:
Let the two-digit number be ab.
Then the given information can be written as:
a = 4b
a + b = 10
(4b) + b = 10 Substitute a = (4b)
5b = 10
b = 2
a = 4b
a = 4(2)
a = 8
The original number is:
ab = 82