Write the first five terms of the sequence with the recursive definition

Question

F(1)=2/3,f(n)=f(n-1)*3/2 for n>2

Answer 1

f(1) = 2/3

f(2) =f(1)(3/2) = 2/3(3/2) = 1

f(3) = f(2)(3/2) = 1(3/2) = 3/2 = 1.5

f(4) = f(3)(3/2) = 3/2(3/2) = 9/4 = 2.25

f(5) = f(4)(3/2) = (9/4)(3/2) = 27/8 = 3.375

3/3, 1, 3/2, 9/4, 27/8