Hello, Roseline,
Given f(x)=1/4(5-x)^2 what is the value of f(11)?
Put "11" in place of every "x" in the equation:
f(11)=1/4(5-11)^2
f(11)=1/4(-6)^2
f(11)=(1/4)(36)
f(11)= (36/4)
f(11) = 9
Bob
Roseline C.
asked • 01/20/21Please help me!
Given f(x)=1/4(5-x)^2 what is the value of f(11)?
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