Solve equation -6+2sinx=sin^2x-5

Answer 1

Given: -6 + 2*sinx = (sinx)^2 - 5

Solve for x.

SOLUTION:

0 = (sinx)^2 - 2*sinx + 1

Let u = sinx

0 = u^2 - 2u + 1

0 = (u - 1)(u - 1)

0 = (u - 1)^2

u = 1

sinx = 1

x = ArcSin(1) = 90 degrees

Answer 2

set the equation to zero and solve sin^2(x) -2sin(x) +1= 0

(sinx -1)(sinx-1) = 0

sin x = 1

x = Pi/2 radians or 90 degrees