Find the dimensions of a rectangle given that its perimeter is 134 cm and its length is 1 cm more than twice its width.

Question

Set up your solution using the variables L for the length, W for the width, and P for the perimeter. 

 

Part a: Using the definition of perimeter, write an equation for P in terms of L and W.

 

Part b: Using the relationship given in the problem statement, write an equation for L in terms of W.

 

Solve the equations from parts a and b.

 

Part c: The length is  cm.

 

Part d: The width is  cm.

Answer 1

P=2(L+W)

L=1+2W

P=2(1+2W+W) =2(1+3W) = 2+6W=134

6W = 134-2 = 132

W = 132/6 = 22 cm

L=1+2W = 1+2(22) = 1+44 = 45 cm