
Bradford T. answered 01/13/21
Retired Engineer / Upper level math instructor
For combined work problems
r1t + r2t = 1
If only the first pipe is open, then
r16 = 1 --> r1= 1/6
If both pipes are open then it only takes 5 hours
r1(5) + r2(5) = 1 --> 5/6 +5r2 = 1 -->r2 = 1/30
For the slower pipe alone,
r2t =t/30 = 1 --> t = 30 hours