Write an equation of the line that passes through (7,10) and is perpendicular to the line y=12x−9.

Answer 1

Use - 1/12 for the slope, the opposite reciprocal of 12, which is the given slope your line is meant to be perpendicular to. Then, one form of the equation you can write is "point-slope."

y - 10 = - 1/12(x - 7)

Answer 2

the slope of the perpendicular MUST be (-1/12)

B = y - mx = 10 - (-1/12)(7) = 10 + 7/12 = 120/12 + 7/12 = 127/12

y = (-1/12)x+ 127/12