Find seven ordered pairs to the equation y=x^2-8

Answer 1

easiest way is just pick some small simple integers for x and plug it into the equation to find y

(0,-8)

(1,-7) 1^2-8 = -7

(2,-4) 2^2-8 = 4-8 = -4

(3,1) etc.

(4,8)

(5,17)

(6,28)

or you could change the sign of the x coordinate to negative and get 7 more ordered pairs