plz convert these URGENT

Question

1. How many molecules in a sample of NaClO with a mass of 3.90g.

2. 2.4g of CO2 would have how many Oxygen atoms.

3. 1.63 x 10^22 molecules of CH3COONa to grams

4. 3.6g AlPO4 to moles

5. 2.4g Na2SO4 to molecules

6. 5.50 x 10^22 atoms CaSO4 to grams

7. 6.8g (NH4)3PO4 to moles

Answer 1

To find moles, divide the mass in grams by the molecular weight

To find number of molecules multiply the number of moles by 6.02 x 10 ^ 23

To convert molecules to grams, divide by 6.02 x 10^23, then multiply by the molecular weight in g

To find molecular weight add up the atomic weight of each atom in the molecule

This is enough background to be able to do these

Answer 2

Let's calculate the conversions for each of the given problems:

1. How many molecules in a sample of NaClO with a mass of 3.90g?

First, find the molar mass of NaClO:

Na: 22.99 g/mol

Cl: 35.45 g/mol

O: 16.00 g/mol

Molar mass of NaClO = 22.99 + 35.45 + 16.00 = 74.44 g/mol

Now, calculate the number of moles in 3.90g of NaClO:

Moles = Mass / Molar mass = 3.90g / 74.44 g/mol ≈ 0.0524 moles

To find the number of molecules, use Avogadro's number (6.022 x 10^23 molecules/mol):

Number of molecules = Moles x Avogadro's number = 0.0524 moles x 6.022 x 10^23 molecules/mol ≈ 3.12 x 10^22 molecules

2. 2.4g of CO2 would have how many Oxygen atoms?

First, calculate the molar mass of CO2:

C: 12.01 g/mol

O: 16.00 g/mol (there are two oxygen atoms in CO2)

Molar mass of CO2 = 12.01 + (2 * 16.00) = 44.01 g/mol

Now, calculate the number of moles in 2.4g of CO2:

Moles = Mass / Molar mass = 2.4g / 44.01 g/mol ≈ 0.0545 moles

Since there are two oxygen atoms in each molecule of CO2, the number of oxygen atoms is doubled:

Number of oxygen atoms = 2 x Moles x Avogadro's number = 2 x 0.0545 moles x 6.022 x 10^23 atoms/mol ≈ 6.19 x 10^22 oxygen atoms

3. 1.63 x 10^22 molecules of CH3COONa to grams:

First, calculate the molar mass of CH3COONa:

C: 12.01 g/mol

H: 1.01 g/mol

O: 16.00 g/mol

Na: 22.99 g/mol

Molar mass of CH3COONa = 12.01 + 3(1.01) + 2(16.00) + 22.99 ≈ 82.02 g/mol

Now, calculate the mass of 1.63 x 10^22 molecules:

Mass = Moles x Molar mass = (1.63 x 10^22 molecules) / (6.022 x 10^23 molecules/mol) x 82.02 g/mol ≈ 2.23 g

4. 3.6g AlPO4 to moles:

First, find the molar mass of AlPO4:

Al: 26.98 g/mol

P: 30.97 g/mol

O: 16.00 g/mol (there are four oxygen atoms in AlPO4)

Molar mass of AlPO4 = 26.98 + 30.97 + 4(16.00) = 122.98 g/mol

Now, calculate the number of moles in 3.6g of AlPO4:

Moles = Mass / Molar mass = 3.6g / 122.98 g/mol ≈ 0.0293 moles

5. 2.4g Na2SO4 to molecules:

First, calculate the molar mass of Na2SO4:

Na: 22.99 g/mol (there are two sodium atoms in Na2SO4)

S: 32.07 g/mol

O: 16.00 g/mol (there are four oxygen atoms in Na2SO4)

Molar mass of Na2SO4 = 2(22.99) + 32.07 + 4(16.00) = 142.05 g/mol

Now, calculate the number of moles in 2.4g of Na2SO4:

Moles = Mass / Molar mass = 2.4g / 142.05 g/mol ≈ 0.0169 moles

To find the number of molecules, use Avogadro's number:

Number of molecules = Moles x Avogadro's number = 0.0169 moles x 6.022 x 10^23 molecules/mol ≈ 1.02 x 10^22 molecules

6. 5.50 x 10^22 atoms CaSO4 to grams:

First, calculate the molar mass of CaSO4:

Ca: 40.08 g/mol

S: 32.07 g/mol

O: 16.00 g/mol (there are four oxygen atoms in CaSO4)

Molar mass of CaSO4 = 40.08 + 32.07 + 4(16.00) = 136.08 g/mol

Now, calculate the mass of 5.50 x 10^22 atoms:

Mass = Moles x Molar mass = (5.50 x 10^22 atoms) / (6.022 x 10^23 atoms/mol) x 136.08 g/mol ≈ 1.25 g

7. 6.8g (NH4)3PO4 to moles:

First, find the molar mass of (NH4)3PO4:

N: 14.01 g/mol (there are three nitrogen atoms in (NH4)3PO4)

H: 1.01 g/mol (there are twelve hydrogen atoms in (NH4)3PO4)

P: 30.97 g/mol

O: 16.00 g/mol (there are four oxygen atoms in (NH4)3PO4)

Molar mass of (NH4)3PO4 = 3(14.01) + 12(1.01) + 30.97 + 4(16.00) = 149.12 g/mol

Now, calculate the number of moles in 6.8g of (NH4)3PO4:

Moles = Mass / Molar mass = 6.8g / 149.12 g/mol ≈ 0.0456 moles