First, let us define some variables.
Let:
-The price for an adult be "A"
-The price for a child be "C"
We will now organize the given information into a system of equations.
(eq. 1)......... 3*A+4*C=$104 [3 adults and 4 children must pay $104]
(eq. 2)......... 2*A+3*C=$73 [2 adults and 3 children must pay $73]
Next, isolate one of the variables (let's do adults "A") for one of the equations (let's us equation 1).
We will subtract the quantity "4*C"to each side of the equation:
3*A+4*C-4*C=$104-4*C
3*A=$104-4*C
Then we will divide both sides of the equation by "3":
(3*A)/3=($104-4*C)/3
(eq. 3)..........A=($104-4*C)/3
We can now substitute equation 3 into equation 2:
2*[($104-4*C)/3]+3*C=$73
Solve for C by multiplying both sides of the equation by 3:
3*{2*[($104-4*C)/3]+3*C}=3*($73)
This leaves us with:
2*($104-4*C) + 9*C=$219
Distributing the 2 gives us:
$208 - 8*C + 9*C = $219
Combining like-terms gives us:
-8*C+9*C= $219 - $208
When simplified is:
C=$11
Having found the price of admission for a child ($11), we can now substitute this value into equation 3:
A= ($104-4*C)/3, with C= $11
A= ($104 - 4 * $11)/3
A= ($104 - $44)/3
A= ($60)/3
A= $20
Final Answer:
Price of Adult Ticket- $20
Price of Child Ticket- $11