Raymond B. answered 01/08/21
Math, microeconomics or criminal justice
2L + 2W = 126
L=8+ 4W
2(8+4W) + 2W = 126
16 + 8W + 2W = 126
10W = 110 cm wide
W = 11
L = 8+44= 52 cm long
Area = LW = 11(52) = 572 cm squared
Kornelius T.
asked 01/08/21The rectangle shown has a perimeter of 126
cm and the given area. Its length is 8 more than four times its width. Write and solve a system of equations to find the dimensions of the rectangle.
(given area is 572 cm squared)
Raymond B. answered 01/08/21
Math, microeconomics or criminal justice
2L + 2W = 126
L=8+ 4W
2(8+4W) + 2W = 126
16 + 8W + 2W = 126
10W = 110 cm wide
W = 11
L = 8+44= 52 cm long
Area = LW = 11(52) = 572 cm squared
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