need help on algebra 2 homework asap

Question

the height of a softball, in feet, is modeled by the function h given by h(t)=3+55t-16t^2, where t is the time, in seconds, after the softball is hit.

a- about when does the softball reach its maximum height?

b- about how high is the maximum height of the softball

c- about when does the ball hit the ground

Answer 1

h'(t) = -32t + 55 = 0

t =55/32 seconds to reach max height, about 1.72 seconds

max height = h(55/32) = -16(55/32)^2 + 55(55/32) + 3 = (55/32)(16(55)/32 +55) + 3 = 55^2/64 +55^2/32 = 3(55^2)/64 = 9075/64 = about 142 feet

h = -16t^2 +55t + 3 = 0

t = 55/32 + or - (1/32)sqr(55^2 +64(3)) = 55/32 + or - (1/32) sqr 9267 = 1.72. + or - 3 = 4.72 seconds when it hits the ground.