Raymond B. answered 01/08/21
Math, microeconomics or criminal justice
5S+7A=2450
S equals the number of student tickets sold, A= the number of adult tickets sold
You can graph this as a straight line, with S on the vertical axis and A on the horizontal axis
y intercept = 2450/5 = 490, x intercept = 2450/7 =350. Those are the maximum number of student or adult tickets that could have been sold. Connect those 2 intercepts with a straight line and any points with integers (A,S) are solutions to the problem.
Usually this type of problem adds a 2nd constraint, the total number of tickets sold.
without that, you get multiple solutions. IF A and S were not required to be integers, you would get an infinite number of solutions.
to get 0 as the last digit for total sales, A has to end in a zero or a 5, such as 300. 300A=2100, then S =350/5 =70
if A = 200, 200A = 1400 and S=2050/5 = 410
Pick any A that ends in a 0 or 5 and there's an S that will also be an integer.
A =10, S=(2450-70)/5 = 2380/5 = 476
A=5 S =(2450-35)/5 =2415/5 = 483
There are about 70 solutions