Algebra math question.

Question

Jane has $4.36, she has double the number of dimes as nickels, one more penny than the number of dimes, and two less quarters than dimes. if she has one dollar bill, how much coins does she have each.

Answer 1

d=2n

n=d/2

p=d+1

q=d-2

b=1

p+5n+10d+25q+100b=436

d+1+5d/2+10d+25(d-2)+100= 436

77d/2 =336+50-1

d=385(2/77)=

10 dimes

8 quarters

5 nickels

11 pennies

1 bill

11+25+100+200+100=436