Explain the question down below.

Question

There is a line that passes through the point (0,3) and has a slope of 2. Its points can be found with the equation y = 2x + 3.

Which method from parts 1, 2, and 3 would you use to graph this line?

Explain how to graph the line using the method you chose.

Answer 1

Hi Mia. As I don't see parts 1, 2 or 3, I'll explain to you generally the methods to graph lines.

y = 2x+3

This equation is in slope-intercept form, y = mx+b, where m is the slope and b is the y-intercept. The y-intercept in our equation is (0,3), so start by plotting that point. Now, use the slope to graph the rest of the line This is done by remembering that slope = rise/run, or slope = (change in y)/(change in x). In our equation, 2 is the slope. This means that the rise is 2 and the run is 1, so for every increase of 1 in x, the height (y) increases by 2.

Now use this information starting at your point (0,3) to plot more points. If x increases by 1, y increases by 2, so other points are at (1, 5), (2, 7), (3, 9), and so on. If x decreases by 1, y decreases by 2, so other points are at (-1,1), (-2, -1), (-3, -3), and so on.