Write an equation of the line that passes through (-3,3) and is perpendicular to the line 2y=8x-6

Answer 1

solve for y in 2y = 8x-6 to get equation in form y=mx+b

(divide both sides by 2)

y = 4x - 3

slope of this line is 4. slope of perpendicular line is negative reciprocal of 4 or -1/4

so equation of that line is:

y = -1/4 x + b

to find b, use (-3,3) to substitute -3 for x and 3 for y in the above equation and solve for b.

3 = -1/4 (-3) + b

9/4 = b

y = -1/4x + 9/4