
Bradford T. answered 12/29/20
Retired Engineer / Upper level math instructor
I assume the units of 60 is miles per hour (mph). If feet per second, then that's a different problem.
60 mph = 60(5280 ft)/(3600 seconds) = 88 ft/second
velocity, v = at
acceleration, a = (88-0)/5.5 = 16 ft/s2
distance s = at2/2 + v0t + s0 , where v0 and s0 are the initial velocity and distance, both zero.
s = 280 ft
t = √(2s/a) = √((2)(280)/(16)) = 5.916 seconds
v = at = 16(5.916) = 94.65 ft/second = (94.65/5280)(3600) = 64.53 mph
Chris S.
Also 64.53 mph is pretty high, did you measure from starting 0 mph?12/29/20
Chris S.
yes you're right, i forgot to add that (MPH). Thank you for your reply!12/29/20