Jen H.

asked • 12/28/20

The equation y-5=m(x-2) represents a line, no matter what value m. Show that the first quadrant triangle is always at least 20.

The equation y-5=m(x-2) represents a line, no matter what value m.

(A) what are the x and y intercepts of this line? I got: 2-5/m =x ; -2m+5=y

(B) for what value of m does this line form a triangle of area 36 with the positive axes? I got m= -1/2 or m=-25/2

(C) The equation y-5=m(x-2) represents a line, no matter what value m. Ans? I am stuck on this one. I multipled x*y=0 and got m=5/2 but i know the slope has to be negative since it's in quadrant one. If i use m=-5/2 and solve for x, y (using answers from a), and then A=(xy)/2, I get 20, but not sure i can just make m negative? (this is an 8th grade question- so pre-calc).

1 Expert Answer

By:

Raymond B. answered • 12/28/20

Tutor
5 (1)

Math, microeconomics or criminal justice

Jen H.

Thank you! It's a challenge problem. Not sure where it's coming from.
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12/29/20

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