
Patrick B. answered 12/23/20
Math and computer tutor/teacher
not ( p v ( not p and q)) =
not p and not ( not p and q) =
not p and (p or not q) =
(not p and p) or (not p and not q)=
F or (not p and not q)
the truth value then depends entirely
upon not p and not q =
not (p or q)
[end of proof]
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(not p or R) or (not q or R) <-- implication identity
(not p or not q ) or (R or R) <--- associative
not (p and q) or R <--- deMorgan's;
(p and q) --> R <-- implication identity