What is the slope of a line perpendicular to the line whose equation is 15x+12y=-10815x+12y=−108. Fully reduce your answer.

Answer 1

To make it easier to look at, first try solving for y with the left and right sides. (You can ignore the middle terms.)

15x + 12y = -108

12y = -108 - 15x

y = -(15/12)x -(108/12)

y = -5/4x - 9

Then determine what is perpendicular to slope -5/4.

To find the slope of a line that is perpendicular to a line with this slope, you need to take the negative reciprocal.

Thus, the answer is 4/5.