Lines p and q are perpendicular Line p is described by the equation 2x-5y = 8. Line q passes through the point (-6,2). Which equation represents line q?

Answer 1

p is -5y = -2x + 8 or y = (2/5)x - 8/5 with slope equal to 2/5. A perpendicular line has a negative inverse slope = -5/2. change the sign and flip the fraction upside down. y=(-5/2)x + b is the equation with b = the y intercept. plug in the point, with x=-6, y =2 to solve for b. 2 = (-5/2)(-6) + b. b = 2-15 =-13

the equation of the perpendicular line is: y=(-5/2)x -13 or 5x+2y = -26