Calculating our position in relation to the sun

Question

Okay, I'm 63, and only went as far as precalculus in school, but that's probably enough to understand the answer. Here's my question:

Imagine a line passing through the center of the sun and the center of the earth. If you draw that line at all points in the earth's revolution around the sun* you have a plane the bisects the earth into two roughly equal half spheres.

*not factoring in the movement of the sun through the galaxy, etc.

At every place where that plane touches the surface of the earth, you have a "solar equator." If you draw a line that passes through the center of the earth perpendicular to that plane, then you have a "solar north pole" and a "solar south pole" on the earth -- points that are constantly moving on the surface of the earth.

Here's my question: My latitude is 43.53 North. But in this system I would also have a "solar latitude" which would be constantly changing. I would like to know my minimum and maximum "solar latitude" in the space of a year, and, more importantly, how much my "solar latitude" could change in a single 24 hour day.

This question came to me as I was pondering how the sun climbs and falls in the sky at an angle or in an arc.

I don't know how to figure that out. Do you?

Answer 1

The 2 diameters of Earth/sun are 2.99*10^11 and 1.495*10^11. This is an oval form. Earth's axis is 23.5°. The radius is 3948.756m.

Oval area=hvπ/2.

To figure distance sun/Earth; for each day there's a different length. You have to get into trig.

The solar system is level.