If tan A = 28/45 and sin B = 24/25 and angles A and B are in Quadrant I, find the value of tan(A+B).

Question

Help me, please! It's due at 1:30!!!

Answer 1

tan A = 28/45

tanA=.6222......

A=31.89°

sin B = 24/25 

sinB=.96

B=73.739...°

A+B=105.63° Which is in quad2. Or -74.369.........° which is in quad4.

tan=-3.5742..........

Answer 2

there're 2 ways go do this. IF you get different answers, at least one is wrong

just calculate A and B, then add then and find the tangent

IF tan A =28/45 then A = 31.9

If sinB = 24/25 then B = 73.7

add them; A+B = 105.6

tan105.6 =-3.6

or use the tan(A+B) formula = (tanA+tanB)/(1-tanAtanB)

tanA= 28/45

IF sinB=24/25, then it's a 7-24-25 right triangle and tanB=24/7

plug those into the formula tan(A+B) = (28/45 + 24/7)/(1-(28/45)(24/7))

tan(A+B) = (1276)/-357=-3,6