Given sin A = (2/ √13) and that angle A is in Quadrant I, find the exact value of tan A in simplest radical form using a rational denominator.

Question

Help me, please! I have to turn it in by 1!!!

Answer 1

sinA = 2/√13

cosA = √(1 - sin²A) = √(1 - 4/13) = √(9/13) = 3/√13

tanA = sinA / cosA = (2/√13) / (3/√13) = 2/3

Answer 2

sinA = 2/√13

cosA = √(1 - sin²A) = √(1 - 4/13) = √(9/13) = 3/√13

tanA = sinA / cosA = (2/√13) / (3/√13) = 2/3