Area, A = length • width = 6w

Power Density, P = 6•18/A = 18/w = 5

w = 18/5 = 3.6 meters

Sarah L.

Thank you
Report

12/23/20

Sarah L.

asked • 12/18/20What is the maximum width of the room if the lamp power density requirement of 5W/m^2 (5 Watts per metre squared) is to be met?

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Area, A = length • width = 6w

Power Density, P = 6•18/A = 18/w = 5

w = 18/5 = 3.6 meters

Sarah L.

Thank you
Report

12/23/20

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Sarah L.

I don't really understand the problem i calculated the problem but i got a different answer can you please explain how you got the answer thank you12/21/20