Area, A = length • width = 6w

Power Density, P = 6•18/A = 18/w = 5

w = 18/5 = 3.6 meters

Bradford T.

tutor

As I understood the problem, it gives you the maximum power density,P, of 5 watts per square meter. This is a constraint. For the total area there will be 6 times 18 Watts used, or 108 watts total spread over the area. The area, A, is length time width, but we don't know the width, w. The length is given as 6, so the area is 6w. But we do know that P is equal to 108/Area = 108/(6w) = 5 watts/m^2. Solving for the width, w = 108/(5*6) = 3.6 watts/m^2.
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12/21/20

Sarah L.

Thank you
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12/23/20

Sarah L.

I don't really understand the problem i calculated the problem but i got a different answer can you please explain how you got the answer thank you12/21/20