Please helppppp i’m in desperate need

Question

the weight W of an object varies inversely as the square of the distance d from the center of the earth. At sea level (3978 mi from the center of the earth) an, astronaut weighs 137 lbs. find her weight when she is about 348 mi above the surface of the earth and the spacecraft is not in motion

Answer 1

If weight W varies inversely with the distance r2 from the center of the earth, then, if k = the proportionality constant

W₁ = k/r₁² _{then 137 = k/(3978)}² _{of k = 2,167,954,308}

_{Then for the second weight at 348 farther, we have}

Weight = (2,167,954,308)/(3978+348)² = 115.85 pounds