Raymond B. answered 12/18/20
Tutor
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Math, microeconomics or criminal justice
d^2 = (x1-x2)^2 + (y1-y2)^2 - 64+ 225 = 289
d = sqr289 = 17
distance squared = sum of the squares of the differences between the x and y coordinates
d^2 = (5--3)^2 = (6--9)^2 = 8^2 +15^2 = 64+225 = 289