
Sanjay S. answered 02/23/15
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Anna has 5 pennies
So remaining coins are 90 in number and the value is $12.00
Let there be d dimes, so there are d + 5 quarters and 90-d-(d+5) nickels
Value of these coins will be
10*d + 25*(d+5) + 5*(90-2d-5) = 1200
10d + 25d + 125 + 450 -10d -25 = 1200
25d + 550 = 1200
d = 26
So there are 26 dimes, 31 quarters and 33 nickels and 5 pennies
Check the answer
26*10 + 31*25 + 33*5 + 5*1 = 1205