
Bradford T. answered 12/16/20
Retired Engineer / Upper level math instructor
Let c = the speed of the current and t be time. Remember d = rt or r = d/t
Rate upstream is 4-c and downstream 4+c
The two equations are derived from both r=d/t:
4-c = 8/t
4+c = 8/(5-t)
Add the two equations
8 = 8/t + 8/(5-t) --> 8= 40/(t(t-5)) --> t = (5 + √5)/2 by picking the positive one
Substitute that into 4-c = 8/t --> c = 8/((5 + √5)/2) - 4 --> c = (4/5)√5