The square root of the sum of a square number increased by 7 added to the number that is equal to 7. What would be the number?

Answer 1

sqr((x+7)^2 + x = 7

x+7 = 7-x

x =-x

x=0, 0 is a square number 0^2 = 0

But the question is a little unclear and ambiguous, so you may mean something else

maybe sqr(x^2 + 7) + x = 7

sqr(x^2+7) = 7-x

x^2+7 = 49-14x+ x^2

7 = 49-14x

14x = 42

x = 42/7 = 6

x = 6

Or you might interpret the problem is some other manner

x=6 is a clue that might be right, when the answer comes out to a simple integer