Word Problems in Algebra

Question

Mofor wants to make 6.5 qt. of a 48% alcohol solution by mixing together a 60% alcohol solution and pure water. How much of each solution must he use?

Answer 1

A+W = 6.5

.48(6.5) = .6A + 0(W)

A = .48(6.5)/.6 = .8(6.5) = 5.2 quarts of 48% alcohol

W = 6.5 -5.2 = 1.3 quarts of water

to get 6.5 quarts of 48% alcohol solution

5.2 quarts times .6 solution = 31.2

6.5 quarts times .48 solution = 31.2

48% is much closer to 60%, than to water's 0%, so the mixture will have much more 48% alcohol than water

it's 12% less than 60% and 4(12%) more than water's 0%

4 times more translates to 5.2 = 4(1.3)