Find the perimeter of ABC with vertices A( 1,-6), B(1,-3) and C(-4,-6)

Answer 1

If you plot the figure, you will see that you have a right triangle with legs of length 3 (between (1,-3 and 1,-6) and 5 (between 1,-6 and -4,-6). Using the Pythagorean Theorem, the length of the hypotenuse is 5.8. So the perimeter is 3 + 5 + 5.8 = 13.8

Answer 2

10 + sqr58 = about 17.62 = perimeter

from C to A is 7

from A to B is 3

that sums to 10

from C to B is the square root of 7^2 + 3^2 = sqr(49+9) = sqr58

AC + AB + BC = 7+3+sqr58 = 10+sqr58 = about 10+7.62 = 17.62