Andre has $12.30 in pennies, nickles, dimes, and quarters. If he has the same number of each coin, how many of each does he have?

Answer 1

Let x = The number of each type of coin

.01x+.05x+.1x+.25x=$12.30

.41x=$12.30

X=30

So there are 30 coins of each type

Answer 2

Since the number of each coin is the same, and that is what you are trying to solve for, set that unknown as X.

So, we know that

X pennies + X nickels+ X dimes + X quarters = $12.30

Let's now represent the coins with the proper value:

.01X + .05X + .10X + .25X= 12.30

Now, simplify. We can add all terms of X together:

.41X = 12.30

To get X alone, divide both sides by .41:

X= 12.30/.41

X=30

Answer 3

x represents the number of each coin

0.01x + 0.05x + 0.10x + 0.25x = 12.30

Can you solve for x and answer?