Determine the Total voltage produced by Gold(III)acetate and calcium metal

Question

Must show all work. Derive using redox reactions.

Answer 1

Let gold(III) acetate be represented as Au(Ac)3 ==> Au3+ + 3Ac-

Reactions involved are as follows:

Au³⁺ + 3e- ==> Au(s) ... Eºred = 1.52V

Ca²⁺ + 2e- ==> Ca(s) ... Eºred = -2.84V

cathode reduction: Au³⁺ + 3e- ==> Au(s) x2

anode oxidation: Ca(s) ==> Ca²⁺+ 2e x3

Overall reaction:

2Au³⁺ + 3Ca(s) ==> 2Au(s) + 3Ca²⁺

Eºcell = 1.52 V - (-2.84 V) = 4.36V