How do I find the equation in standard form of the parabola passing through the points (-8, 8), (2, -12) and (6, -6)

Answer 1

use the standard form equation. y=ax^2 + bx +c and plug in each point to get 3 equations, 3 unknowns. solve for a,b and c with matrix algebra or substitution and elimination.

I get a= 7/4, b = 25/3 c= -1/4

or y= (7/4)x^2 + (25/3)x - 1/4

anyway, that's the method(s). I might have made an arithmetic mistake but maybe not. It gets tedious.