Inactive Tutor answered 12/10/20
Prob(ACE) = 4/52 = 1/13
Prob(FACE) = 12/52 = 6/26= 3/13
Prob(other) = 36/52 = 18/26 = 9/13
(12-2)*1/13 + (3-2)*3/13 + (0-2)*9/13 =
10/13 + 1/13 -18/13 =
-7/13 =
-0.53846153846153846153846153846154
Ma F.
asked 12/10/20In a game that costs $2 to play, a player selects a card at random from a standard deck. The player earns $12 for selecting an ace, $3 for selecting a face card, and nothing for selecting any other card. Find the expected value of net gain OR loss.
Inactive Tutor answered 12/10/20
Prob(ACE) = 4/52 = 1/13
Prob(FACE) = 12/52 = 6/26= 3/13
Prob(other) = 36/52 = 18/26 = 9/13
(12-2)*1/13 + (3-2)*3/13 + (0-2)*9/13 =
10/13 + 1/13 -18/13 =
-7/13 =
-0.53846153846153846153846153846154
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