
Karina F. answered 12/10/20
If you seek success...I am here to help
Interesting...
Think of the FLAT FEE as the initial value of y when x = 0. This point will be (0, 30) and the function for when the mileage is 0 - 15 will be: y OR f(x) = 30.
For any value of x (up to 15), y = 30. This is a horizontal line on the graph.
When the mileage ranges from 16 - 30, there is NO flat fee and now y or f(x) is dependent on the value of x (miles) and the rate (or slope) of $1.10/mile, The company simply charges for the miles driven.
y OR f(x) = 1.10x
When the mileage is > 30, there is NO flat fee and now y or f(x) is dependent on the value of x (miles) and the rate (or slope) of $1.20/mile, so:
y OR f(x) = 1.20x
So f(12) is the value of y when x = 12. Since 12 is btw 0 - 15, the value of y or f(x) will meet condition #1 (mileage btw 0 and 15), where only the FLAT FEE is charged
f(12) = 30
The ordered point will be (12, 30)
For f(23), the value of x is now btw (16 - 30) meeting the 2nd condition. So you need to compute the value of y or f(x) when x = 23 using the 2nd function f(x) = 1.10x
f(23) = 1.10x = 1.10(23) = 25.3
The ordered point will be (23, 25.3)
Same as above, f(37) = 1.20x (because it meets the 3rd condition x or the mileage is > 30)
f(37) = 1.20x = 1.20(37) = 44.4
The ordered point will be (37, 44.4)
For the last part of the problem, you are given the value of y or f(x), so you have to determine the corresponding x value.
f(x) = $51.70 and f(x) $28.80
From the previous calculations, I think its safe to assume that with f(x) = 51.70 the value of x will be greater than 30 (meeting the 3rd condition) since at x = 37, y was equal to 44.4.
f(x) = 1.20x
51.70 = 1.20x
Solve for x
x = 51.70/1.20 = 43.08 or 43.1
So this ordered point will be (43.1, 51.7)
f(x) = 28.80, it is safe to assume that the value of x will fall btw 16 and 30, because its value is very clost to the value of f(x) when x was equal to 23, meeting the 2nd condition
f(x) = 1.10x
28.80 = 1.10x
Solve for x
x = 28.80/1.10 = 26.1
So this ordered point will be (26.1, 28.8)
Hope this helps :)