homework help problem

Question

Rana purchased some beef and some chicken for a family barbeque. The beef was $6.00 a pound and the chicken cost $4.50 per pound He bough 18 pounds of meat and spent $96. How many pounds of beef and how many pounds of chicken did he buy?

Answer 1

B+C = 18

C=18-B

6B+4.5C=96

6B +4.5(18-B) = 96

1.5B =96-81=15

B = 15/1.5 =10 pounds

C=18-10 = 8 pounds

Answer 2

Hey Chase,

Let's walk through this problem.

What are you trying to figure out? how many pounds of beef and how how many pounds of chicken to buy

Let x = pounds of beef to buy; let y = pounds of chicken to buy

What do we know?

1. beef cost $6 per pound; chicken cost $4.50 per pound (think we don't know how many pounds yet, right?) but she spent a total of $96
2. total number of pounds is 18 (well, how many pounds are beef and how many are chicken? We don't know yet.)

Put it all together:

$6 times the number of pounds of beef + $4.50 times the number of pounds of chicken totals $96

6x + 4.50y = 96

18 total pounds = the number of pounds of beef + the number of pounds of chicken

18 = x + y

Now that I help you set it up. Can you solve for x and y? There are multiple ways to try. I hope this helps.

Answer 3

Let x = the number of pounds of beef and y = the number of pounds of chicken.

x+y = 18

6x+ 4.5y = 96

y = 18-x

6x +4.5(18-x) = 6x + 81 -4.5x = 96

1.5x = 15 --> x = 10 and y = 18-10 = 8