Since P(A intersection B)=0 we have that P(A union B)=P(A)+P(B) which implies that P(B)=P(A union B)-P(A)=0.8-0.4=0.4.
Jaime C.
asked • 12/07/20A ∩ B = ∅, P(A) = 0.4, P(A ∪ B) = 0.8. Find P(B).
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