please help me quick i've been stuck on this question forever :(

Question

If (x - 3)2 = 5, then what values of x make the quadratic equation true? Write your answer in brackets.

Answer 1

If (x - 3)2 = 5, then what values of x make the quadratic equation true? Write your answer in brackets.

The equation should be read as

(x-3)² = 5

which is

x² -6x+9 = 5

or

x² -6x +4 = 0

which is quadratic

having roots as

x = ( 3 +√5 ) and x = (3 -√5)

Answer 2

Two ways to solve this:

(x-3)² = 5

x-3 = ±√5

x= 3+√5, 3-√5

or

(x-3)² = x²-6x+9 = 5

x²-6x+4 = 0

Quadratic equation:

x = (6 ±√(36 - 16))/2 = (6 ±√20)/2 = (6 ±2√5)/2 = 3±√5

x= 3+√5, 3-√5

Not sure what they meant by "Write your answer in brackets."