Line r has an equation of y=x+5. Parallel to line s, which passes through the point (2, 2). What is the equation of line s

Answer 1

Given that the equation of line r is y = 1x + 5, the slope of line r would be 1.

If line s is parallel to line r, it would also have a slope of 1. Since a point on line s is (2,2) you should start with point-slope form to solve for the equation of line s.

Using point-slope form, the equation of line s would be:

y - y1 = m(x - x1)

y - 2 = 1(x - 2) This is the equation in point-slope form.

If you had to change the form back into slope intercept form:

y - 2 = 1(x - 2)

y - 2 = 1x - 2

y = 1x + 0

y = 1x

y = x This is the equation in slope-intercept form

In standard form, you could write the equation as:

-x + y = 0, or

x - y = 0