find two consecutive odd integers such that the smaller one is ten more than one- fifth the larger.

Question

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Answer 1

Let the smaller consecutive odd integer = X

Then the larger consecutive odd integer = X + 2

 

The smaller one is ten more than one-fifth the larger  ==>  

 

X = 10 + (1/5)*(X + 2)

X = 10 + (1/5)*X + (2/5)

(4/5)*X = (52/5)

X = (52/5) * (5/4) = 13

 

So the two consecutive odd integers are 13 and 15.