The admission to the fair is 5$ and the cost per ride is 50¢. If your parents give you 20$ write and solve a linear equation to find how many rides you can go on

Answer 1

Let x be the number of rides you can go then $0.5x is the cost of the rides.

Putting a together we form an equation:

$5+$0.5x=$20

or

5+0.5x=20

Solving for x:

0.5x=20-5

0.5x=15

x=30

Answer 2

Hope this helps...

When you get a problem like this with an initial cost like the $5 fair admission that tells you that at

x = 0, y = 5. So if you were to graph the line (that you will come up with) the line will start (or cross the

y-axis) at ordered point (0, 5.)

And when you are given a 'rate' like $0.50 per ride...that is the slope, m of your line / function.

Think about variable x as '# of rides' versus variable y as 'the amount of money you have'

Would you agree that for every ride you pay $0.50? So then after 10 rides, you have spent $0.50(10) = $5

Know the number of rides, x is dependent on how much money you have ($20), the cost per ride ($0.50) and how you spend on the admission fee ($5) OR in other words the number of rides you can ride, x times the cost per ride ($0.50/ride) and the admission fee have to equal the amount of money that you have ($20.)

So...the linear function for this is y = 0.50x + 5

We can solve for x, because y = 20 (the amount of money you can spend)

20 = 0.50x + 5

20 - 5 = 0.50x + 5 - 5 .... isolate the x term by taking the 5 to the LHS

15 = 0.50x ...solve for x by dividing both sides by 0.50

x = 30 rides Final Answer