Algebra 1 Substitution

Question

Use substitution to solve the system of equations. Type your answer in coordinate format: (x,y)

2x-3y=-28

x+6y=16

Answer 1

First you'll rearrange x+6y=16 to be x=16-6y.

Then, you'll substitute that into the other equation, like so:

2(16-6y)-3y=-28

32-12y-3y=-28

Simplifying the equation yields 60=15y. Solving the equation yields y=4.

This y value can now be plugged back into the other equation to solve for x.

x=16-6y

x=16-6(4)=16-24=-8

Putting it into a coordinate format, (x,y)=(-8,4).