verify the identity , show steps

Question

((sec beta -tan beta )^(2)+1)/(csc beta (sec beta -tan beta )=2 tan beta

Answer 1

((secβ-tanβ)^2+1)/(cscβ(secβ-tanβ)) =

(sec²β+tan²β-2secβtanβ+1)/(cscβ(secβ-tanβ)) = as tan²β+1 = sec²β

(2sec²β-2secβtanβ)/(cscβ(secβ-tanβ)) =

2secβ(secβ-tanβ)/(cscβ(secβ-tanβ))=

2secβ/cscβ =

2tanβ