what makes y+10= -2/7(x-5) perpendicular ?

Answer 1

Hello, Kayla,

A perpendicular line to an equation of the form y = mx + b will have a slope (m) that is the negative inverse of m, or (-1/m). y = -(1/m)x + b is perpendicular to y = mx + b.

Simplify the equation to see this.

y = -(2/7)x + 10/7 -10

y = -(2/7)x - (60/7)

The line perpendicular to this is y = (7/2)x + b, where b is the y intercept, -(60/7) in the original line. The new line can have the same, or other intercept, but I'll simply us the same one here:

y = (7/2)x - (60/7)

Answer 2

Make the slope, -2/7, into its negative inverse, 7/2.